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Another puzzle.

#1 User is offline   OleBerg 

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Posted 2010-March-05, 12:53

Construct a full deal where, with best defence and declarer play:

- NS will score 9 tricks in NT.
- 28 HCP' are unblocked (Including forced unblocking.)

Winner gets a no-prize.
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Do not underestimate the power of the dark side. Or the ninth trumph.

Best Regards Ole Berg

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We should always assume 2/1 unless otherwise stated, because:

- If the original poster didn't bother to state his system, that means that he thinks it's obvious what he's playing. The only people who think this are 2/1 players.


Gnasher
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#2 User is offline   gwnn 

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Posted 2010-March-05, 14:03

I am sorry but what is the precise definition of unblocking and forced unblocking? And how do you measure it in HCP's?
... and I can prove it with my usual, flawless logic.
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#3 User is offline   OleBerg 

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Posted 2010-March-05, 16:31

Good question!

I meant "Forced" unblocking to be the case, where a hand has to follow to partners trick with a highcard that could have won the trick, if partner had played a small instead. Or if the card is of equal strength to the trick-winning card.

Unblocking is simply throwing winning cards on other winners.

Edit:

So if you throw an ace on a winning deuce, you have unblocked 4 HCP.
If a hand plays the king, dropping partners queen, you have unblocked 2 HCP. (Provided either hand had a small card they could have followed with.
_____________________________________

Do not underestimate the power of the dark side. Or the ninth trumph.

Best Regards Ole Berg

_____________________________________

We should always assume 2/1 unless otherwise stated, because:

- If the original poster didn't bother to state his system, that means that he thinks it's obvious what he's playing. The only people who think this are 2/1 players.


Gnasher
0

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