A priori, KJx on right will occur 11%, K singleton on left 13%.
If I play the ace, then I gain one MP (half a US MP) from the other pairs in slam if I am right.
If I guess to play the ten, then I gain one MP from the other pairs in 6
♠ and *two* MP (one US MP) from the other pairs in 4
♠.
This analysis suggests that the breakeven point is when one-twelfth of the other tables don't bid slam, which in most fields is enough evidence to take the safety play IMO.
[snip a load of stuff based on 6NT making

]
BTW Luke, is the field 10 tables or 20? Not that it should make any difference to our decision
This post has been edited by MickyB: 2005-April-22, 03:21