You hold
!S: ---
!H: KJ932
!D: Q543
!C: AKJ7
You deal and find your hand worth a 1!H bid. The first round proceeds:
1!H - (2!S) - 3!D - (3!S)
What now? I'm a little excited about the 3!D bid, and decide on a 4!S rebid.
4!S - (P) - 4N - (P)
Well, it's the 40th board you've played with this partner, you don't know, but assume 4NT is key-card asking.
Taking the low road, you respond 5!D (3014):
5!D - (P) - 5!H - (P)
Oh, heck, what's that? Queen ask? I've got it, and the king of clubs, so ...
6!C - (P) - 6!H - (P)
Gads. Maybe P was trying to get to hearts all this time? Guess it's time to pass...

P - (P)
The !SA comes out from LHO's hand, and dummy is revealed (your hand repeated for your convenience):
!S: K953
!H: QT76
!D: AT7
!C: Q6
!S: ---
!H: KJ932
!D: Q743
!C: AKJ7
OK, bucky, how are you going to come to 12 tricks?
(So as to not spoil it for others, please send me a personal email on BBO ("ThomasRush") and I'll summarize the results in a few days, giving people credit for correct solutions)
Things you might want to know: !H are 3-1; if you lead a heart to the queen, RHO wins the ace and returns a spade.
There aren't any weird suit splits; each opponent has at least two diamonds and at least two clubs.
LHO's 2!S bid was a 'standard' preemptive jump overcall (like a weak 2 bid, if that helps).
Yeah, so Partner should probably cuebid 3!S (Limit raise or better) instead of the rather unusual 3!D call... but then you might not have gotten to slam, so "God bless you, partner (if I make it)."
I'd call this an intermediate play of the hand problem. You should be able to develop a plan for 12 tricks at trick 1.