What this 2NT means?
#1
Posted 2005-November-07, 20:20
1♦=1♥=dbl=pass
2♣=2♥=pas=pass
2nt
what is it?
thanks
000002
#3
Posted 2005-November-07, 21:04
#4
Posted 2005-November-07, 22:06
A 3C rebid would show 5-5 minors. The 2NT bid 'shows' 6D and 4C and still lets partner choose which minor to play.
If the other pair bids (1S)-2m-(2S)-p-p-? when you overcall in a minor, you can bid 2NT to suggest four hearts plus 5+ of your minor. If you only held the minors, you would bid 3Cs and let partner 'pick' a suit.
Regards,
Robert
#5
Posted 2005-November-08, 06:22
Robert, on Nov 7 2005, 11:06 PM, said:
A 3C rebid would show 5-5 minors. The 2NT bid 'shows' 6D and 4C and still lets partner choose which minor to play.
If the other pair bids (1S)-2m-(2S)-p-p-? when you overcall in a minor, you can bid 2NT to suggest four hearts plus 5+ of your minor. If you only held the minors, you would bid 3Cs and let partner 'pick' a suit.
Regards,
Robert
2N is certainly 6♦ and 4♣.
I disagree with the other example, though: (1S)-2m-(2S)-P-(P)-?
Now, X is m+H; 2N is m+om. when m is significantly better than om, this sequence applies even when m=♦. 3♣ would mean 5-4 or 5-5; 2N again 6-4
#7
Posted 2005-November-08, 14:13
#8
Posted 2005-November-08, 14:16
- hrothgar
#9
Posted 2005-November-08, 21:01
did you open 1C with 5c+4d & 11-13HCP?
what 3D rebid?7cards ♦?
#10
Posted 2005-November-08, 21:10
000002, on Nov 8 2005, 10:01 PM, said:
did you open 1C with 5c+4d & 11-13HCP?
what 3D rebid?7cards ♦?
The only reason to want to compete with a 5-4 is a lot of strength (19?); your pard has never shown a sign of life.
I would re-open with a double, in such a case.
With 5♣ and 4♦ i would open 1♦ with all hand weaker than reverse.
3♦ should be 6 strong diamonds.
With 7 diamonds i would not have re-bid 2♣
#11
Posted 2005-November-09, 02:03
|
| WOULD you to compete? |
regards
#12
Posted 2005-November-09, 02:28
000002, on Nov 9 2005, 10:03 AM, said:
|
| WOULD you to compete? |
regards
No, because I can never expect partner to chose the right minor. Note how much better this hand works if you start with 1♣: You can bid 2♦ over the double, and you are done.
Arend
#13 Guest_Jlall_*
Posted 2005-November-09, 07:49
000002, on Nov 9 2005, 03:03 AM, said:
|
| WOULD you to compete? |
regards
no
#16
Posted 2005-November-09, 23:32
What do you do with a strong 1345 or 1354 if
(1S)-2m-(2S)-p-p-X=hearts and the minor? I play that as 1336 1354 1345
or 1363 My normal style would be to just double 1S with 13 majors and 54 minors.
If you promise 4 hearts to double 1S, you have to overcall a 5m or pass.
With 1435 or 1453 why didn't you just double one spade 'if' you have the values to compete at the three level?
Squire(bright green cover) book and others suggest using 2NT to show the odd suit.
Do you really bid (1S)-2D-(2S)-p-p-3C on a 5D-4C hand? A new 4 card minor suit at the three level and partner has never even 'hinted' at values or a fit?
Regards,
Robert
#17
Posted 2005-November-10, 06:09
The another important associated question:
1♦===1♥===dbl===pass
2♣===2♥===pas===pass
dbl?
Is it an intense suggestion for penalty ?
#18
Posted 2005-November-10, 07:01
#19
Posted 2005-November-10, 11:26
I would agree that 2nT is for takout and asks partner to choose from 6-4, but I think it needs prior agreement
#20
Posted 2005-November-10, 17:49
Robert, on Nov 10 2005, 12:32 AM, said:
What do you do with a strong 1345 or 1354 if
(1S)-2m-(2S)-p-p-X=hearts and the minor? I play that as 1336 1354 1345
or 1363 My normal style would be to just double 1S with 13 majors and 54 minors.
If you promise 4 hearts to double 1S, you have to overcall a 5m or pass.
With 1435 or 1453 why didn't you just double one spade 'if' you have the values to compete at the three level?
Squire(bright green cover) book and others suggest using 2NT to show the odd suit.
Do you really bid (1S)-2D-(2S)-p-p-3C on a 5D-4C hand? A new 4 card minor suit at the three level and partner has never even 'hinted' at values or a fit?
Regards,
Robert
Hi, Robert.
My style is to double 1♠ with 4♥, if the double is backed by limited strength; the more off-shape it si, the more strong it must be.
Therefore i would double 1♠ with 1-3-4-5 with a good 15/+ HCP. However, the quality of the suits plays an obvious role. With x, Jxx, AKQxx, KQJx I would prefer 2♦; with x, AQx, KJxxx, KQJx I would certainly double.
Now suppose that I have not that strength, but a good ♦ suit (1-3-5-4). I would prefer to bid 2♦, and when the bid comes back to me at 2♠, to double to show ♣ and tolerance for ♥ (note that if the hand were 1-4-3-5 or 1-4-5-3 i would have no qualm in doubling 1♠).
If I were to bid 3♣, it would show a 5-5. Now you may argue that I did not use the unusual NT over 1♠: this would be because my ♦ are significantly stronger than ♣.
This frees up 2NT for 6♦ and 4♣. I would not care to compete with 2-2-5-4, unless it were something like xx xx AKJxx AQJx. In which case, i'd use 2NT again
Does it make sense?
I will welcome your input.
regards

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